### The Math Beast Challenge Problem of the Week – December 9, 2013

If

xandyare integers such thatx<yandxy= 4, which of the following could be the value of 2x+ 4y?

** To see this week’s answer choices and to submit your pick, visit our Challenge Problem page.**

### The Math Beast Challenge Problem of the Week – November 25, 2013

If

nis a positive integer greater than 1, then the functionp(n) represents the product of all the prime numbers less than or equal ton. Which of the following is the second smallest prime factor ofp(11) + 12?

** To see this week’s answer choices and to submit your pick, visit our Challenge Problem page.**

### The Math Beast Challenge Problem of the Week – November 11, 2013

- Quantity A is greater.
- Quantity B is greater.
- The two quantities are equal.
- The relationship cannot be determined from the information given.

** To see this week’s answer choices and to submit your pick, visit our Challenge Problem page.**

### Manhattan GRE’s Halloween Challenge Problem

We hope everyone had a happy Halloween! Yesterday we asked our friends on our Manhattan GRE Facebook page to attempt this Trick-or-Treat Halloween Challenge Problem. As promised, today we are sharing the answer and explanation to the problem:

Let’s use *x* for the number of bags produced by the original recipe, and *y *for the weight of each of the bags. Given those variables, our first equation is simply *xy* = 600. We also need to create an equation that represents the new recipe. Since the number of bags produced has increased by 30, and the weight of each bag has decreased by 1, the new equation is (*x* + 30)(*y* – 1) = 600. Remember, the total weight is still 600 ounces. Foiling this equation yields *xy* – *x* + 30*y* – 30 = 600.

We now have two equations with two variables. There are several different paths we can go down here, but all involve substitution of one of the variables, and all will yield a quadratic. The simplest path is to recognize that since *xy* = 600, we can substitute for *xy* in the second equation to get 600 – *x* + 30*y* – 30 = 600. Subtracting the 600 from both sides, and adding an *x* to each side gives us 30*y* – 30 = *x.* We can now substitute for *x* in the first equation.

### The Math Beast Challenge Problem of the Week – October 28, 2013

If

xis a positive integer and the first nonzero digit in the decimal expansion of is in the hundredths place, what is the value ofx?

**Submit your pick over on our Challenge Problem page.**

### The Math Beast Challenge Problem of the Week – October 21, 2013

The outer figure above is a rectangle with four rounded corners of radius equal to 2. The inner figure is a circle.

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### The Math Beast Challenge Problem of the Week – October 14, 2013

Xander, Yolanda, and Zelda each have at least one hat. Zelda has more hats than Yolanda, who has more than Xander. Together, the total number of hats the three people have is 12. If Zelda has no more than 5 hats more than Xander, which of the following could be the number of hats that Yolanda has?

See the answer choices and submit your pick over on our Challenge Problem page.

### The Math Beast Challenge Problem of the Week – October 7, 2013

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### The Math Beast Challenge Problem of the Week – September 23, 2013

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### The Math Beast Challenge Problem of the Week – September 16, 2013

See the answer choices and submit your pick over on our Challenge Problem page.