Ben Ku wrote:Nitin did a great job of explaining it.
Sharmin: it would be helpful to write a bit of explanation about how you got to your answer, or where you got stuck. THen we can respond to your confusion directly.
The key to this problem is knowing that when we have an odd number of consecutive integers, the mean = median. So the question can be rephrased: "what is the 6th integer"?
Statement (1) is a set of the first nine integers, so the mean = median = 7 = 5th integer. Well, the 6th integer then is 8, so (1) is sufficient.
If eleven consecutive integers are listed from least to greatest, what is the average (arithmetic mean) of the eleven integers?
You can use the same reasoning to determine that (2) is also sufficient.
Know this is an old post but I am very curious. Question to Ben Ku:
Why should we have only ODD number of consecutive integers to say that mean=median in a consecutive list of integers?
I think it works for EVEN number of consecutive integers as well. E.g. 1,2,3,4,5,6 (in total 6 integers).
Mean=(1+6)/2=3.5 [in consecutive list of integers, mean equals (1st number+last number)/2]
Thanks for clarifying.