{"id":9516,"date":"2015-06-04T16:03:10","date_gmt":"2015-06-04T16:03:10","guid":{"rendered":"http:\/\/www.manhattanprep.com\/gmat\/?page_id=9516"},"modified":"2015-06-10T17:21:52","modified_gmt":"2015-06-10T17:21:52","slug":"errata-fom-4ed","status":"publish","type":"page","link":"https:\/\/www.manhattanprep.com\/gmat\/errata\/errata-fom-4ed\/","title":{"rendered":"Errata – Foundations of Math, 4th Edition"},"content":{"rendered":"
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Errata – Foundations of GMAT Math, 4th Edition<\/h2>\r\n \r\n <\/div>\r\n <\/div>\r\n<\/div>\r\n\r\n
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Foundations of GMAT Math (Edition 4.1)<\/h2>\r\n \r\n \r\n \r\n \r\n \r\n
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\r\n Edition 4.2<\/h4>\r\n <\/th>\r\n

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\r\n Edition 4.1<\/h4>\r\n <\/th>\r\n

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\r\n Edition 4.0<\/h4>\r\n <\/th>\r\n <\/tr>\r\n <\/thead>\r\n

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\r\n Release Date:<\/strong>\r\n
August, 2010<\/p>\r\n

\r\n Differentiating Mark:<\/strong><\/p>\r\n

\r\n \"4.2 Back Cover, Bottom Right Corner<\/p>\r\n <\/td>\r\n

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\r\n Release Date:<\/strong>\r\n
December 1, 2009<\/p>\r\n <\/td>\r\n

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\r\n Release Date:<\/strong>\r\n
May 1, 2009<\/p>\r\n <\/td>\r\n <\/tr>\r\n <\/tbody>\r\n <\/table>\r\n

\r\n The Foundations of GMAT Math Strategy Supplement (326 pages) provides a refresher of the basic math topics tested on the GMAT. Designed to be user-friendly for all students, this book provides easy-to-follow explanations of fundamental math concepts and step-by-step application of these concepts to example problems.\r\n <\/p>\r\n

4.2<\/h2>\r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n
Page<\/th>\r\n Loc<\/th>\r\n Description<\/th>\r\n Erroneous Text<\/th>\r\n Correction<\/th>\r\n <\/tr>\r\n <\/thead>\r\n
\r\n 54\r\n <\/td>\r\n \r\n Bot\r\n <\/td>\r\n \r\n The second sentence under the “Factoring Quadratic Equations” Heading factors the equation incorrectly.\r\n <\/td>\r\n \r\n It's not easy to look at x2<\/sup> + 3x – 10 and see that it equals (x – 5)(x + 2).\r\n <\/td>\r\n \r\n It's not easy to look at x2<\/sup> + 3x – 10 and see that it equals (x + 5)(x – 2).\r\n <\/td>\r\n <\/tr>\r\n
\r\n 287\r\n <\/td>\r\n \r\n Mid\r\n <\/td>\r\n \r\n In the second sentence of the explanation for #6, the 2 in the expression should be an exponent.\r\n <\/td>\r\n \r\n The radius of the circle is 10, so the area is ?<\/i>(10)2, which equals 100?<\/i>.\r\n <\/td>\r\n \r\n The radius of the circle is 10, so the area is ?<\/i>(10)2<\/sup>, which equals 100?<\/i>.\r\n <\/td>\r\n <\/tr>\r\n
\r\n 300\r\n <\/td>\r\n \r\n Mid\r\n <\/td>\r\n \r\n Drill Set 3, Drill 2, #5: Question refers to Triangle XYZ, but the picture depicts Triangle ABC.\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n <\/tr>\r\n
\r\n 300\r\n <\/td>\r\n \r\n Mid\r\n <\/td>\r\n \r\n Drill Set 3, Drill 2, #5: Question fails to mention that Triangle XYZ is a right triangle.\r\n <\/td>\r\n \r\n Triangle XYZ and Rectangle JKLM have equal areas…\r\n <\/td>\r\n \r\n Right Triangle XYZ and Rectangle JKLM have equal areas…\r\n <\/td>\r\n <\/tr>\r\n
\r\n 134\r\n <\/td>\r\n \r\n Mid\r\n <\/td>\r\n \r\n Drill Set 2, Drill 4, #1: The prime factorization of 18 given in the explanation is incorrect. 18 = 2 \u00d7 3 \u00d7 3, NOT 2 \u00d7 2 \u00d7 3 \u00d7 3.\r\n <\/td>\r\n \r\n 18 = 2 \u00d7 2 \u00d7 3 \u00d7 3, so 18 contains two 2's and two 3's. x contains two 2's, but…\r\n <\/td>\r\n \r\n 18 = 2 \u00d7 3 \u00d7 3, so 18 contains one 2 and two 3's. x contains one 2, but…\r\n <\/td>\r\n <\/tr>\r\n
\r\n 315\r\n <\/td>\r\n \r\n Bot\r\n <\/td>\r\n \r\n Explanation for Drill Set 3, Drill 2, #5: Question refers to Triangle XYZ, but the picture depicts Triangle ABC.\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n <\/tr>\r\n <\/tbody>\r\n <\/table>\r\n

4.1<\/h2>\r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n
\r\n Page\r\n <\/th>\r\n \r\n Loc\r\n <\/th>\r\n \r\n Description\r\n <\/th>\r\n \r\n Erroneous Text\r\n <\/th>\r\n \r\n Correction\r\n <\/th>\r\n <\/tr>\r\n <\/thead>\r\n
\r\n 67\r\n <\/td>\r\n \r\n Mid\r\n <\/td>\r\n \r\n Set 2, Drill 4, #3. + should be –\r\n <\/td>\r\n \r\n x3<\/sup> – 3x2<\/sup> + 28x = 0\r\n <\/td>\r\n \r\n x3<\/sup> – 3x2<\/sup> – 28x = 0\r\n <\/td>\r\n <\/tr>\r\n
\r\n 287\r\n <\/td>\r\n \r\n Mid\r\n <\/td>\r\n \r\n In the second sentence of the explanation for #6, the 2 in the expression should be an exponent.\r\n <\/td>\r\n \r\n The radius of the circle is 10, so the area is ?<\/i>(10)2, which equals 100?<\/i>.\r\n <\/td>\r\n \r\n The radius of the circle is 10, so the area is ?<\/i>(10)2<\/sup>, which equals 100?<\/i>.\r\n <\/td>\r\n <\/tr>\r\n
\r\n 134\r\n <\/td>\r\n \r\n Mid\r\n <\/td>\r\n \r\n Drill Set 2, Drill 4, #1: The prime factorization of 18 given in the explanation is incorrect. 18 = 2 \u00d7 3 \u00d7 3, NOT 2 \u00d7 2 \u00d7 3 \u00d7 3.\r\n <\/td>\r\n \r\n 18 = 2 \u00d7 2 \u00d7 3 \u00d7 3, so 18 contains two 2's and two 3's. x contains two 2's, but…\r\n <\/td>\r\n \r\n 18 = 2 \u00d7 3 \u00d7 3, so 18 contains one 2 and two 3's. x contains one 2, but…\r\n <\/td>\r\n <\/tr>\r\n
\r\n 54\r\n <\/td>\r\n \r\n Bot\r\n <\/td>\r\n \r\n The second sentence under the “Factoring Quadratic Equations” Heading factors the equation incorrectly.\r\n <\/td>\r\n \r\n It's not easy to look at x2<\/sup> + 3x – 10 and see that it equals (x – 5)(x + 2).\r\n <\/td>\r\n \r\n It's not easy to look at x2<\/sup> + 3x – 10 and see that it equals (x + 5)(x – 2).\r\n <\/td>\r\n <\/tr>\r\n
\r\n 300\r\n <\/td>\r\n \r\n Mid\r\n <\/td>\r\n \r\n Drill Set 3, Drill 2, #5: Question refers to Triangle XYZ, but the picture depicts Triangle ABC.\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n <\/tr>\r\n
\r\n 315\r\n <\/td>\r\n \r\n Bot\r\n <\/td>\r\n \r\n Explanation for Drill Set 3, Drill 2, #5: Question refers to Triangle XYZ, but the picture depicts Triangle ABC.\r\n <\/td>\r\n <\/tr>\r\n
\r\n 155\r\n <\/td>\r\n \r\n Mid\r\n <\/td>\r\n \r\n Set 1, Drill 2, #9. The explanation incorrectly switches from z to x.\r\n <\/td>\r\n \r\n x(5 + (-3) – (-8))<\/sup> = x10<\/sup>\r\n <\/td>\r\n \r\n z(5 + (-3) – (-8))<\/sup> = z10<\/sup>\r\n \r\n <\/td>\r\n <\/tr>\r\n
\r\n 256\r\n <\/td>\r\n \r\n Top\r\n <\/td>\r\n \r\n There is a typo in the second sentence at the top of the page.\r\n <\/td>\r\n \r\n A right triangle is any triangle in which one of the angles is a right triangle.\r\n <\/td>\r\n \r\n A right triangle is any triangle in which one of the angles is a right angle.\r\n <\/td>\r\n <\/tr>\r\n
\r\n 247\r\n <\/td>\r\n \r\n Bot\r\n <\/td>\r\n \r\n Incorrect description of diameter in the text box.\r\n <\/td>\r\n \r\n d = diameter the distance around a circle\r\n <\/td>\r\n \r\n d = diameter the distance across a circle\r\n <\/td>\r\n <\/tr>\r\n
\r\n 300\r\n <\/td>\r\n \r\n Mid\r\n <\/td>\r\n \r\n Drill Set 3, Drill 2, #5: Question fails to mention that Triangle XYZ is a right triangle.\r\n <\/td>\r\n \r\n Triangle XYZ and Rectangle JKLM have equal areas…\r\n <\/td>\r\n \r\n Right Triangle XYZ and Rectangle JKLM have equal areas…\r\n <\/td>\r\n <\/tr>\r\n
\r\n 67\r\n <\/td>\r\n \r\n Mid\r\n <\/td>\r\n \r\n Set 2, Drill 4, #5. – 9x should be + 9x\r\n <\/td>\r\n \r\n -3x3<\/sup> + 6x2<\/sup> – 9x = 0\r\n <\/td>\r\n \r\n -3x3<\/sup> + 6x2<\/sup> + 9x = 0\r\n <\/td>\r\n <\/tr>\r\n
\r\n 233\r\n <\/td>\r\n \r\n Top\r\n <\/td>\r\n \r\n Set 1, Drill 1, #1. x < 4 should be x > 4.\r\n <\/td>\r\n \r\n x < 4\r\n <\/td>\r\n \r\n x > 4\r\n <\/td>\r\n <\/tr>\r\n
\r\n 224\r\n <\/td>\r\n \r\n Bot\r\n <\/td>\r\n \r\n In the first paragraph after the chart, change divide to multiply.\r\n <\/td>\r\n \r\n In each case, we begin with a true inequality statement: 5 < 7 and then divide by -1.\r\n <\/td>\r\n \r\n In each case, we begin with a true inequality statement: 5 < 7 and then multiply by -1.\r\n <\/td>\r\n <\/tr>\r\n
\r\n 98\r\n <\/td>\r\n \r\n Top\r\n <\/td>\r\n \r\n In the top line, the M should be a C.\r\n <\/td>\r\n \r\n Insert S – 14 for M in the second equation.\r\n <\/td>\r\n \r\n Insert S – 14 for C in the second equation.\r\n <\/td>\r\n <\/tr>\r\n
\r\n 47\r\n <\/td>\r\n \r\n Top\r\n <\/td>\r\n \r\n Drill 1, question 4 does not match the answer explanation provided on page 48.\r\n <\/td>\r\n \r\n 13 \u00d7 6\r\n <\/td>\r\n \r\n 113 \u00d7 6\r\n <\/td>\r\n <\/tr>\r\n
\r\n 300\r\n <\/td>\r\n \r\n Top\r\n <\/td>\r\n \r\n Set 3, Drill 2, #3. Side AD has a length of 8.\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n <\/tr>\r\n
\r\n 34\r\n <\/td>\r\n \r\n Mid\r\n <\/td>\r\n \r\n Set 2, Drill 4, #8. Answer explanation on page 38 is incorrect. See below.\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n <\/tr>\r\n
\r\n 129\r\n <\/td>\r\n \r\n Bot\r\n <\/td>\r\n \r\n Set 1, Drill 2, #3. Prime factorization is incorrect. The upper left circle should contain a 2, not a 5.\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n <\/tr>\r\n
\r\n 36\r\n <\/td>\r\n \r\n Mid\r\n <\/td>\r\n \r\n Set 1 Drill 4 is mislabeled..\r\n <\/td>\r\n \r\n Set 1, Drill 5:<\/b>\r\n <\/td>\r\n \r\n Set 1, Drill 4:<\/b>\r\n <\/td>\r\n <\/tr>\r\n
\r\n 314\r\n <\/td>\r\n \r\n Bot\r\n <\/td>\r\n \r\n Set 3, Drill 2, #3. Side AD has a length of 8.\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n <\/tr>\r\n
\r\n 240\r\n <\/td>\r\n \r\n Mid\r\n <\/td>\r\n \r\n Set 5, Drill 2, #5. The inequality below the number line incorrectly switches <= to <. Also, the circles on the number line should be filled in.\r\n <\/td>\r\n \r\n -12 < x < 8\/3\r\n <\/td>\r\n \r\n -12 <= x <= 8\/3\r\n <\/td>\r\n <\/tr>\r\n
\r\n 239\r\n <\/td>\r\n \r\n Bot\r\n <\/td>\r\n \r\n Set 5, Drill 2, #2. The inequality below the number line is incorrect.\r\n <\/td>\r\n \r\n -14 < x < 6\r\n <\/td>\r\n \r\n x < -14 or x > 6\r\n <\/td>\r\n <\/tr>\r\n
\r\n 239\r\n <\/td>\r\n \r\n Bot\r\n <\/td>\r\n \r\n Set 5, Drill 2, #2. The number line is incorrect. The circles should be blank, not filled.\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n <\/tr>\r\n
\r\n 232\r\n <\/td>\r\n \r\n Mid\r\n <\/td>\r\n \r\n Set 5, Drill 2, #2. Answer explanation on pg 239 incorrect. See error below.\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n <\/tr>\r\n
\r\n 239\r\n <\/td>\r\n \r\n Bot\r\n <\/td>\r\n \r\n Set 5, Drill 2, #3. The explanation incorrectly switches from < to <=.\r\n <\/td>\r\n \r\n |x3<\/sup>| <= 64\r\n
+ (x3<\/sup>) <= 64 \u00a0\u00a0\u00a0 or \u00a0\u00a0\u00a0 -(x3<\/sup>) <= 64\r\n
\u00a0\u00a0\u00a0 x3<\/sup> <= 64 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 -x3<\/sup> <= 64\r\n
\u00a0\u00a0\u00a0 x <= 4 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 x3<\/sup> >= -64\r\n
\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 x >= -4\r\n <\/td>\r\n 		\r\n |x3<\/sup>| < 64\r\n
+ (x3<\/sup>) < 64 \u00a0\u00a0\u00a0 or \u00a0\u00a0\u00a0 -(x3<\/sup>) < 64\r\n
\u00a0\u00a0\u00a0 x3<\/sup> < 64 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 -x3<\/sup> < 64\r\n
\u00a0\u00a0\u00a0 x < 4 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 x3<\/sup> > -64\r\n
\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 x > -4\r\n <\/td>\r\n <\/tr>\r\n
\r\n 123\r\n <\/td>\r\n \r\n Top\r\n <\/td>\r\n \r\n Question #12 on page 111 has been amended. Refer to the listing on page 111.\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n <\/tr>\r\n
\r\n 74\r\n <\/td>\r\n \r\n Top\r\n <\/td>\r\n \r\n Set 2, Drill 4, #3. The first two lines of the explanation\r\n <\/td>\r\n \r\n x3<\/sup> – 3x2<\/sup> + 28x = 0\r\n
x(x\r\n 2<\/sup> – 3x + 28) = 0 -> x(x – 4)(x + 1) = 0\r\n <\/td>\r\n 		\r\n x3<\/sup> – 3x2<\/sup> – 28x = 0\r\n
x(x\r\n 2<\/sup> – 3x – 28) = 0 -> x(x – 7)(x + 4) = 0\r\n <\/td>\r\n <\/tr>\r\n
\r\n 74\r\n <\/td>\r\n \r\n Mid\r\n <\/td>\r\n \r\n Set 2, Drill 4, #5. The first two lines of the explanation\r\n <\/td>\r\n \r\n -3x3<\/sup> + 6x2<\/sup> – 9x = 0\r\n
-3x(x\r\n 2<\/sup> – 2x + 3) = 0 -> -3x(x – 3)(x + 1) = 0\r\n <\/td>\r\n 		\r\n -3x3<\/sup> + 6x2<\/sup> + 9x = 0\r\n
-3x(x\r\n 2<\/sup> – 2x – 3) = 0 -> -3x(x – 3)(x + 1) = 0\r\n <\/td>\r\n <\/tr>\r\n
\r\n 130\r\n <\/td>\r\n \r\n Bot\r\n <\/td>\r\n \r\n Set 1, Drill 4, #2. Ignore 3rd sentence.\r\n <\/td>\r\n \r\n 937,184 ends in 4, which means it's even. Therefore, it's divisible by 2. It's also divisible by 1 and. Prime numbers have only two factors…\r\n <\/td>\r\n \r\n 937,184 ends in 4, which means it's even. Therefore, it's divisible by 2. Prime numbers have only two factors…\r\n <\/td>\r\n <\/tr>\r\n
\r\n 38\r\n <\/td>\r\n \r\n Bot\r\n <\/td>\r\n \r\n Set 2, Drill 4, #8. Introduces a negative sign into the second line of the explanation.\r\n <\/td>\r\n \r\n 10(-3x + 4) = 2(10 – 5x)\r\n
-30x + 40 = 20 – 10x\r\n
40 = 20 + 20x\r\n
20 = 20x\r\n
1 = x\r\n <\/td>\r\n 		\r\n 10(3x + 4) = 2(10 – 5x)\r\n
30x + 40 = 20 – 10x\r\n
40x + 40 = 20\r\n
40x = -20\r\n
x = -1\/2\r\n <\/td>\r\n <\/tr>\r\n
\r\n 131\r\n <\/td>\r\n \r\n Mid\r\n <\/td>\r\n \r\n Set 1, Drill 6. 5 is prime and should be bolded.\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n <\/tr>\r\n
\r\n 131\r\n <\/td>\r\n \r\n Bot\r\n <\/td>\r\n \r\n Set 1, Drill 6. 27 is not prime.\r\n <\/td>\r\n \r\n Prime numbers: 2, 3, 5, 7, 17, 27, 29, 31\r\n <\/td>\r\n \r\n Prime numbers: 2, 3, 5, 7, 17, 29, 31\r\n <\/td>\r\n <\/tr>\r\n
\r\n 87\r\n <\/td>\r\n \r\n Mid\r\n <\/td>\r\n \r\n Set 2, Drill 5, #3. Eliminate last year.\r\n <\/td>\r\n \r\n If Joanna's team won 10 games last year, how many games did Eleanor's team win?\r\n <\/td>\r\n \r\n If Joanna's team won 10 games, how many games did Eleanor's team win?\r\n <\/td>\r\n <\/tr>\r\n
\r\n 92\r\n <\/td>\r\n \r\n Top\r\n <\/td>\r\n \r\n Set 2, Drill 2, #4. Change miles to kilometers.\r\n <\/td>\r\n \r\n Answer: Ben ran 11 miles.\r\n <\/td>\r\n \r\n Answer: Ben ran 11 kilometers.\r\n <\/td>\r\n <\/tr>\r\n
\r\n 71\r\n <\/td>\r\n \r\n Bot\r\n <\/td>\r\n \r\n Set 2, Drill 2, #4. The answers are incorrect.\r\n <\/td>\r\n \r\n Answer: c<\/i> = -21 OR -3\r\n <\/td>\r\n \r\n Answer: c<\/i> = 21 OR 2\r\n <\/td>\r\n <\/tr>\r\n
\r\n 111\r\n <\/td>\r\n \r\n Bot\r\n <\/td>\r\n \r\n CYS #12. Change 240 to 120.\r\n <\/td>\r\n \r\n 12. Find the prime factorization of 240.\r\n <\/td>\r\n \r\n 12. Find the prime factorization of 120.\r\n <\/td>\r\n <\/tr>\r\n
\r\n 38\r\n <\/td>\r\n \r\n Bot\r\n <\/td>\r\n \r\n Set 2, Drill 4, #8. Explanation needs to be replaced.\r\n <\/td>\r\n \r\n \u00a0\r\n <\/td>\r\n \r\n 10(3x + 4) = 2(10 – 5x)\r\n
30x + 40 = 20 – 10x\r\n
40x + 40 = 20\r\n
40x = -20\r\n
x = -1\/2\r\n <\/td>\r\n <\/tr>\r\n <\/tbody>\r\n <\/table>\r\n <\/div>\r\n <\/div>\r\n<\/div>","protected":false},"excerpt":{"rendered":"

Errata – Foundations of GMAT Math, 4th Edition Foundations of GMAT Math (Edition 4.1) Edition 4.2 Edition 4.1 Edition 4.0 Release Date: August, 2010 Differentiating Mark: Back Cover, Bottom Right Corner Release Date: December 1, 2009 Release Date: May 1, 2009 The Foundations of GMAT Math Strategy Supplement (326 pages) provides a refresher of the […]<\/p>\n","protected":false},"author":111,"featured_media":0,"parent":9417,"menu_order":0,"comment_status":"open","ping_status":"open","template":"","meta":{"footnotes":""},"yst_prominent_words":[],"class_list":["post-9516","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/www.manhattanprep.com\/gmat\/wp-json\/wp\/v2\/pages\/9516","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.manhattanprep.com\/gmat\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/www.manhattanprep.com\/gmat\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gmat\/wp-json\/wp\/v2\/users\/111"}],"replies":[{"embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gmat\/wp-json\/wp\/v2\/comments?post=9516"}],"version-history":[{"count":3,"href":"https:\/\/www.manhattanprep.com\/gmat\/wp-json\/wp\/v2\/pages\/9516\/revisions"}],"predecessor-version":[{"id":9655,"href":"https:\/\/www.manhattanprep.com\/gmat\/wp-json\/wp\/v2\/pages\/9516\/revisions\/9655"}],"up":[{"embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gmat\/wp-json\/wp\/v2\/pages\/9417"}],"wp:attachment":[{"href":"https:\/\/www.manhattanprep.com\/gmat\/wp-json\/wp\/v2\/media?parent=9516"}],"wp:term":[{"taxonomy":"yst_prominent_words","embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gmat\/wp-json\/wp\/v2\/yst_prominent_words?post=9516"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}