{"id":8197,"date":"2015-06-10T19:33:48","date_gmt":"2015-06-10T19:33:48","guid":{"rendered":"http:\/\/www.manhattanprep.com\/gre\/?page_id=8197"},"modified":"2015-06-16T18:27:35","modified_gmt":"2015-06-16T18:27:35","slug":"errata-algebra-2ed","status":"publish","type":"page","link":"https:\/\/www.manhattanprep.com\/gre\/errata\/errata-algebra-2ed\/","title":{"rendered":"Errata &#8211; Algebra, 2nd Edition"},"content":{"rendered":"<div class=\"container content-template-container\">\r\n    <div class=\"row\">\r\n        <div class=\"col-sm-12\">\r\n            <h2>Errata &#8211; Algebra, 2nd Edition<\/h2>\r\n        <\/div>\r\n    <\/div>\r\n<\/div>\r\n\r\n<div class=\"container content-template-container\">\r\n\r\n\r\n    <div class=\"row\">\r\n\r\n        <div class=\"col-sm-12\">\r\n\r\n\r\n            <div id=\"dynamicevents\" style=\"margin-top:0px;margin-bottom:0px;\">\r\n            <\/div>\r\n            <p>\r\n                <img decoding=\"async\" alt=\"\" src=\"\/\/cdn2.manhattanprep.com\/gre\/wp-content\/uploads\/sites\/19\/2015\/06\/2nd-ed-algebra-gre.png\" style=\"height: 188px; width: 145px;\" \/>\r\n                <br \/> Cover for 2nd Edition<\/p>\r\n            <h2 class=\"header\">\r\n    2.0<\/h2>\r\n            <table class=\"table table-bordered table-striped\">\r\n                <thead>\r\n<tr>\r\n                        <th>\r\n                            Page<\/th>\r\n                        <th>\r\n                            Location<\/th>\r\n                        <th>\r\n                            Description<\/th>\r\n                        <th>\r\n                            Erroneous Text<\/th>\r\n                        <th>\r\n                            Correction<\/th>\r\n                    <\/tr>\r\n                <\/thead>\r\n                    <tbody>\r\n                        <tr>\r\n                            <td> 34<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> Subtraction result (last line)<\/td>\r\n                            <td> \u00a0= 12<\/td>\r\n                            <td> \u00a04 squareroot[(<em>x<\/em> \u2013 6)] = 12<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 42<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> #8, first line of solution, right of : sign.\u00a0 Subsequent calculations are correct.<\/td>\r\n                            <td> [11 &#8211; 3(x + 4)] \/ (x &#8211; 3) = 7<\/td>\r\n                            <td> [11 + 3(<em>x<\/em> + 4)] \/ (<em>x<\/em> &#8211; 3) = 7<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 56<\/td>\r\n                            <td> Middle<\/td>\r\n                            <td> Factoring of <em>x<\/em><sup>2<\/sup> + 3<em>x<\/em> \u2013 10<\/td>\r\n                            <td> (<em>x<\/em> \u2013 5)(<em>x<\/em> + 2)<\/td>\r\n                            <td> (<em>x<\/em> + 5)(<em>x<\/em> \u2013 2)<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 58<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> logic\/correctness<\/td>\r\n                            <td> our solutions are NEGATIVE 3 and NEGATIVE 4<\/td>\r\n                            <td> our solutions are NEGATIVE 3 or NEGATIVE 4<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 73<\/td>\r\n                            <td> Middle<\/td>\r\n                            <td> #7<\/td>\r\n                            <td> the height, <em>H<\/em>,<\/td>\r\n                            <td> the height in meters, <em>H<\/em>,<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 73<\/td>\r\n                            <td> Middle<\/td>\r\n                            <td> #7<\/td>\r\n                            <td> (how fast Hugo throws it when it leaves his hand)<\/td>\r\n                            <td> (how fast, in meters per second, Hugo throws it as it leaves his hand)<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 73<\/td>\r\n                            <td> Middle<\/td>\r\n                            <td> #7<\/td>\r\n                            <td> time it takes to hit the ground.<\/td>\r\n                            <td> time it takes to hit the ground, in seconds.<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 76<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> #8, &#8220;L&#8221; computation<\/td>\r\n                            <td> Squareroot7 \u00d7 Squareroot7 = -7<\/td>\r\n                            <td> -Squareroot7 \u00d7 Squareroot7 = -7<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 91<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> Grammar<\/td>\r\n                            <td> only scenarios which produce positive products.<\/td>\r\n                            <td> only scenarios that produce positive products.<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 97<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> #27 explanation<\/td>\r\n                            <td> <em>a<\/em> can be positive or negative,<\/td>\r\n                            <td> <em>a<\/em> can be positive, zero, or negative,<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 97<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> #27 explanation<\/td>\r\n                            <td> so <em>ab<\/em> can be positive and negative.<\/td>\r\n                            <td> so <em>ab<\/em> can be positive, zero, or negative.<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 120<\/td>\r\n                            <td> Middle<\/td>\r\n                            <td> #11 explanation<\/td>\r\n                            <td> <em>S<\/em><sub>2<\/sub> = (10.5 + <em>S<\/em><sub>2<\/sub>)\/2<\/td>\r\n                            <td> <em>S<\/em><sub>3<\/sub> = (10.5 + <em>S<\/em><sub>2<\/sub>)\/2<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 140<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> #4 answer<\/td>\r\n                            <td> <strong><em>j<\/em> = 0 OR\u00a0<em>k<\/em> = 4<\/strong><\/td>\r\n                            <td> <strong><em>j<\/em> = 0 AND\/OR <em>k<\/em> = 4<\/strong><\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 140<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> #5 answer<\/td>\r\n                            <td> <strong><em>x<\/em> = 0 OR <em>y<\/em> = 0 OR <em>x<\/em> = -2<\/strong><\/td>\r\n                            <td> <strong>(<em>x<\/em> = 0 OR -2) AND\/OR <em>y<\/em> = 0<\/strong><\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 159<\/td>\r\n                            <td> Middle<\/td>\r\n                            <td> #15 (resulting quadratic is not easily factored with printed numbers)<\/td>\r\n                            <td> Administrative law: 16%<\/td>\r\n                            <td> Administrative law: 15%<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 165<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> Inaccurate language: colloquial use of &#8220;difference&#8221; vs. mathematical definition of &#8220;difference.&#8221;<\/td>\r\n                            <td> Thus, <em>x<\/em> \u2013 <em>y<\/em> is the difference between Quantity A and Quantity B<\/td>\r\n                            <td> Divide both Quantities by (<em>x<\/em> + <em>y<\/em>) to cancel that common positive factor. Now compare Quantity A: (<em>x<\/em> \u2013 <em>y<\/em>) to Quantity B: 1.<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 169<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> Last sentence<\/td>\r\n                            <td> solving first for <em>y<\/em> and then using that value to find <em>x<\/em> and <em>z<\/em>.<\/td>\r\n                            <td> solving first for <em>x<\/em> and then using that value to find <em>y<\/em> and <em>z<\/em>.<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 176<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> #15 explanation<\/td>\r\n                            <td> 21 + <em>x<\/em><sup>2<\/sup> + (<em>x<\/em> + 1) + 16 + 22 + 17 + <em>x<\/em> = 100<\/td>\r\n                            <td> 21 + <em>x<\/em><sup>2<\/sup> + (<em>x<\/em> + 1) + 15 + 22 + 17 + <em>x<\/em> = 100<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 177<\/td>\r\n                            <td> Middle<\/td>\r\n                            <td> #19 explanation of Choice D<\/td>\r\n                            <td> (7 is larger than 2)<\/td>\r\n                            <td> (7 is larger than 4)<\/td>\r\n                        <\/tr>\r\n                    <\/tbody>\r\n            <\/table>\r\n        <\/div>\r\n    <\/div>\r\n<\/div>","protected":false},"excerpt":{"rendered":"<p>Errata &#8211; Algebra, 2nd Edition Cover for 2nd Edition 2.0 Page Location Description Erroneous Text Correction 34 Bottom Subtraction result (last line) \u00a0= 12 \u00a04 squareroot[(x \u2013 6)] = 12 42 Top #8, first line of solution, right of : sign.\u00a0 Subsequent calculations are correct. [11 &#8211; 3(x + 4)] \/ (x &#8211; 3) = [&hellip;]<\/p>\n","protected":false},"author":111,"featured_media":0,"parent":8123,"menu_order":0,"comment_status":"open","ping_status":"open","template":"","meta":{"footnotes":""},"yst_prominent_words":[],"class_list":["post-8197","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/pages\/8197","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/users\/111"}],"replies":[{"embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/comments?post=8197"}],"version-history":[{"count":3,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/pages\/8197\/revisions"}],"predecessor-version":[{"id":8334,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/pages\/8197\/revisions\/8334"}],"up":[{"embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/pages\/8123"}],"wp:attachment":[{"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/media?parent=8197"}],"wp:term":[{"taxonomy":"yst_prominent_words","embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/yst_prominent_words?post=8197"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}