{"id":8201,"date":"2015-06-10T19:33:58","date_gmt":"2015-06-10T19:33:58","guid":{"rendered":"http:\/\/www.manhattanprep.com\/gre\/?page_id=8201"},"modified":"2015-06-16T18:27:49","modified_gmt":"2015-06-16T18:27:49","slug":"errata-fdp-2ed","status":"publish","type":"page","link":"https:\/\/www.manhattanprep.com\/gre\/errata\/errata-fdp-2ed\/","title":{"rendered":"Errata &#8211; Fractions, Decimals, &#038; Percents, 2nd Edition"},"content":{"rendered":"<div class=\"container content-template-container\">\r\n    <div class=\"row\">\r\n        <div class=\"col-sm-12\">\r\n            <h2>Errata &#8211; Fractions, Decimals, &#038; Percents, 2nd Edition<\/h2>\r\n        <\/div>\r\n    <\/div>\r\n<\/div>\r\n\r\n<div class=\"container content-template-container\">\r\n\r\n\r\n    <div class=\"row\">\r\n\r\n        <div class=\"col-sm-12\">\r\n\r\n\r\n            <div id=\"dynamicevents\" style=\"margin-top:0px;margin-bottom:0px;\">\r\n            <\/div>\r\n            <p>\r\n                <img decoding=\"async\" alt=\"\" src=\"\/\/cdn2.manhattanprep.com\/gre\/wp-content\/uploads\/sites\/19\/2015\/06\/2nd-ed-fdp-gre.png\" style=\"height: 188px; width: 145px;\" \/>\r\n                <br \/> Cover for 2nd Edition<\/p>\r\n            <h2 class=\"header\">\r\n    2.0<\/h2>\r\n            <table class=\"table table-bordered table-striped\">\r\n                <thead>\r\n<tr>\r\n                        <th>\r\n                            Page<\/th>\r\n                        <th>\r\n                            Location<\/th>\r\n                        <th>\r\n                            Description<\/th>\r\n                        <th>\r\n                            Erroneous Text<\/th>\r\n                        <th>\r\n                            Correction<\/th>\r\n                    <\/tr>\r\n                <\/thead>\r\n                    <tbody>\r\n                        <tr>\r\n                            <td style=\"text-align: left;\"> 36<\/td>\r\n                            <td> Middle<\/td>\r\n                            <td> Example of converting to a common denominator<\/td>\r\n                            <td> 1\/4 + 5\/5 = 5\/20<\/td>\r\n                            <td> 1\/4 \u00d7 5\/5 = 5\/20<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td style=\"text-align: left;\"> 38<\/td>\r\n                            <td> Middle<\/td>\r\n                            <td> Check Your Skills #6 is incomplete<\/td>\r\n                            <td> \u00a0<em>x<\/em>\/3 &#8211; 4\/9 =<\/td>\r\n                            <td> \u00a0<em>x<\/em>\/3 &#8211; 4\/9 = 8\/9<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td style=\"text-align: left;\"> 41<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> Clarity\/Grammar<\/td>\r\n                            <td> we want to keep 1 of each those smaller pieces.<\/td>\r\n                            <td> we want to keep 1 from each pair of those smaller pieces.<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td style=\"text-align: left;\"> 57<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> #5 explanation<\/td>\r\n                            <td> <em>x<\/em>\/5 + 13\/5 &#8211; 2\/5<\/td>\r\n                            <td> <em>x<\/em>\/5 = 13\/5 &#8211; 2\/5<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td style=\"text-align: left;\"> 58<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> #23 answer<\/td>\r\n                            <td> <strong>1\/13:<\/strong><\/td>\r\n                            <td> <strong>1\/3:<\/strong><\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td style=\"text-align: left;\"> 59<\/td>\r\n                            <td> Middle<\/td>\r\n                            <td> #29 explanation<\/td>\r\n                            <td> more than 170\/340, and so is less than 1\/2<\/td>\r\n                            <td> more than 170\/340, and so is more than 1\/2.<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td style=\"text-align: left;\"> 59<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> #24 answer should be the <em>smaller<\/em> fraction<\/td>\r\n                            <td> <strong>5\/9:<\/strong><\/td>\r\n                            <td> <strong>7\/13:<\/strong><\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td style=\"text-align: left;\"> 62<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> Stray \u00d7 mark in space between Quantity A and Quantity B<\/td>\r\n                            <td> \u00d7<\/td>\r\n                            <td> \u00a0<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td style=\"text-align: left;\"> 63<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> #1 explanation (mathematical completeness)<\/td>\r\n                            <td> Multiplying the numerator of a positive fraction increases the numerator.<\/td>\r\n                            <td> Multiplying the numerator of a positive fraction by a number greater than 1 increases the numerator.<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td style=\"text-align: left;\"> 64<\/td>\r\n                            <td> Middle<\/td>\r\n                            <td> #12 explanation<\/td>\r\n                            <td> since 24 us the least common multiple<\/td>\r\n                            <td> since 24 is the least common multiple<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td style=\"text-align: left;\"> 71<\/td>\r\n                            <td> Middle<\/td>\r\n                            <td> Typo in example of dividing by 10<\/td>\r\n                            <td> 89.507\/10 = 8.3708<\/td>\r\n                            <td> 83.708\/10 = 8.3708<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td style=\"text-align: left;\"> 74<\/td>\r\n                            <td> Middle<\/td>\r\n                            <td> Redundant fraction<\/td>\r\n                            <td> 45\/900 = 45\/900 = 5\/100 = 0.05<\/td>\r\n                            <td> 45\/900 = 5\/100 = 0.05<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td style=\"text-align: left;\"> 84<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> #10 explanation<\/td>\r\n                            <td> 0.00081\/0.91 = 0.081\/9<\/td>\r\n                            <td> 0.00081\/0.09 = 0.081\/9<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td style=\"text-align: left;\"> 92<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> Spelling<\/td>\r\n                            <td> ORIGIANL \u00b1 CHANGE = NEW<\/td>\r\n                            <td> ORIGINAL \u00b1 CHANGE = NEW<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td style=\"text-align: left;\"> 97<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> Spelling in #7<\/td>\r\n                            <td> ORIGIANL<\/td>\r\n                            <td> ORIGINAL<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 97<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> #7<\/td>\r\n                            <td> 35(1.2) = 4.2<\/td>\r\n                            <td> 35(1.2) = 42<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 97<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> Spelling in #8<\/td>\r\n                            <td> ORIGIANAL<\/td>\r\n                            <td> ORIGINAL<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 99<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> #3<\/td>\r\n                            <td> From 1991 to 2000,<\/td>\r\n                            <td> From 1990 to 2000,<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 101<\/td>\r\n                            <td> Middle<\/td>\r\n                            <td> Spelling in #2<\/td>\r\n                            <td> ORIGIANAL \u00d7 (1 ? Percent Decrease\/100)<\/td>\r\n                            <td> ORIGINAL \u00d7 (1 ? Percent Decrease\/100)<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 101<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> #3<\/td>\r\n                            <td> From 1991 to 2000,<\/td>\r\n                            <td> From 1990 to 2000,<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 102<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> Clarity in #6<\/td>\r\n                            <td> There are 1\/4 cups in the bowl<\/td>\r\n                            <td> There are 1\/4 cups of water in the bowl<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 102<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> Clarity in #6<\/td>\r\n                            <td> Alternately, the 4 cups added to the bowl<\/td>\r\n                            <td> Alternatively, the 4 cups of water added to the bowl<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 102<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> Clarity in #6<\/td>\r\n                            <td> there are 14 (50% of 20 + 4) cups in the bowl<\/td>\r\n                            <td> there are 14 (4 + 50% of 20) cups of water in the bowl<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 102<\/td>\r\n                            <td> Middle<\/td>\r\n                            <td> Spelling in #7<\/td>\r\n                            <td> ORIGIANAL \u00d7 (1 ? Percent Decrease\/100)<\/td>\r\n                            <td> ORIGINAL \u00d7 (1 ? Percent Decrease\/100)<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 123<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> #15 explanation (last line)<\/td>\r\n                            <td> <em>Z<\/em> = 100\/<em>Y<\/em><\/td>\r\n                            <td> <em>Z<\/em> = 100<em>X<\/em>\/<em>Y<\/em><\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 135<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> #4 answer<\/td>\r\n                            <td> <strong>7\/200:<\/strong><\/td>\r\n                            <td> <strong>7\/20:<\/strong><\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 149<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> #5 answer choice labels<\/td>\r\n                            <td> (E), (F), (G), (H), (E)<\/td>\r\n                            <td> (A), (B), (C), (D), (E)<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 151<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> #11 answer choice labels<\/td>\r\n                            <td> (I), (J), (K), (L), (E)<\/td>\r\n                            <td> (A), (B), (C), (D), (E)<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 155<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> #4 answer choice format<\/td>\r\n                            <td> (A), (B), (C)<\/td>\r\n                            <td> A, B, C in boxes<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 156<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> #9 clarity<\/td>\r\n                            <td> In 2000, the same group of salaries<\/td>\r\n                            <td> In 2000, the salaries of the same group of clerks<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 157<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> #10: &#8220;3\/8 of the 420 juniors&#8221; would imply that a half person could exist<\/td>\r\n                            <td> 420 Juniors<\/td>\r\n                            <td> 440 Juniors<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 164<\/td>\r\n                            <td> Top<\/td>\r\n                            <td> #12 answer<\/td>\r\n                            <td> <strong>B:<\/strong><\/td>\r\n                            <td> <strong>A:<\/strong><\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 167<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> #4<\/td>\r\n                            <td> (lets use <em>x<\/em>)<\/td>\r\n                            <td> (let&#8217;s use <em>x<\/em>)<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 172<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> #19 answer<\/td>\r\n                            <td> <strong>B:<\/strong><\/td>\r\n                            <td> <strong>C:<\/strong><\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 172<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> #19 explanation<\/td>\r\n                            <td> 0.3<sup>2<\/sup>\/0.02 = 0.09\/0.02 = 9\/2<\/td>\r\n                            <td> 0.3<sup>2<\/sup>\/0.2 = 0.09\/0.2 = 9\/20<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 172<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> #19 explanation<\/td>\r\n                            <td> (3\/2)\/(9\/2) = 1\/3.<\/td>\r\n                            <td> (3\/2)\/(9\/20) = 10\/3.<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 176<\/td>\r\n                            <td> Middle<\/td>\r\n                            <td> #4 explanation<\/td>\r\n                            <td> Squareroot(1\/4) > [Squareroot(1\/4)]\/(1\/4)<\/td>\r\n                            <td> Squareroot(1\/4) < [Squareroot(1\/4)]\/(1\/4)<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 178<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> #10 explanation<\/td>\r\n                            <td> multiply by 420 to determine<\/td>\r\n                            <td> multiply by 440 to determine<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 178<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> #10 explanation<\/td>\r\n                            <td> 420 \u00d7 3\/20 = 3 \u00d7 420\/20 = 3 \u00d7 21 = 63<\/td>\r\n                            <td> 440 \u00d7 3\/20 = 3 \u00d7 440\/20 = 3 \u00d7 22 = 66<\/td>\r\n                        <\/tr>\r\n                        <tr>\r\n                            <td> 181<\/td>\r\n                            <td> Bottom<\/td>\r\n                            <td> #19 explanation<\/td>\r\n                            <td> 45 \u00d7 89 = 2,2<u>05<\/u><\/td>\r\n                            <td> 45 \u00d7 89 = 4,0<u>05<\/u><\/td>\r\n                        <\/tr>\r\n                    <\/tbody>\r\n            <\/table>\r\n        <\/div>\r\n    <\/div>\r\n<\/div>","protected":false},"excerpt":{"rendered":"<p>Errata &#8211; Fractions, Decimals, &#038; Percents, 2nd Edition Cover for 2nd Edition 2.0 Page Location Description Erroneous Text Correction 36 Middle Example of converting to a common denominator 1\/4 + 5\/5 = 5\/20 1\/4 \u00d7 5\/5 = 5\/20 38 Middle Check Your Skills #6 is incomplete \u00a0x\/3 &#8211; 4\/9 = \u00a0x\/3 &#8211; 4\/9 = 8\/9 [&hellip;]<\/p>\n","protected":false},"author":111,"featured_media":0,"parent":8123,"menu_order":0,"comment_status":"open","ping_status":"open","template":"","meta":{"footnotes":""},"yst_prominent_words":[],"class_list":["post-8201","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/pages\/8201","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/users\/111"}],"replies":[{"embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/comments?post=8201"}],"version-history":[{"count":4,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/pages\/8201\/revisions"}],"predecessor-version":[{"id":8335,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/pages\/8201\/revisions\/8335"}],"up":[{"embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/pages\/8123"}],"wp:attachment":[{"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/media?parent=8201"}],"wp:term":[{"taxonomy":"yst_prominent_words","embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/yst_prominent_words?post=8201"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}