{"id":8203,"date":"2015-06-10T19:34:04","date_gmt":"2015-06-10T19:34:04","guid":{"rendered":"http:\/\/www.manhattanprep.com\/gre\/?page_id=8203"},"modified":"2015-06-16T18:27:51","modified_gmt":"2015-06-16T18:27:51","slug":"errata-geometry-2ed","status":"publish","type":"page","link":"https:\/\/www.manhattanprep.com\/gre\/errata\/errata-geometry-2ed\/","title":{"rendered":"Errata – Geometry, 2nd Edition"},"content":{"rendered":"
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Errata – Geometry, 2nd Edition<\/h2>\r\n <\/div>\r\n <\/div>\r\n<\/div>\r\n\r\n
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Cover for 2nd Edition<\/p>\r\n

\r\n 2.0<\/h2>\r\n \r\n \r\n\r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n \r\n
\r\n Page<\/th>\r\n \r\n Location<\/th>\r\n \r\n Description<\/th>\r\n \r\n Erroneous Text<\/th>\r\n \r\n Correction<\/th>\r\n <\/tr>\r\n <\/thead>\r\n
40<\/td>\r\n Middle<\/td>\r\n #3 explanation<\/td>\r\n shaded region represents 3\/4 the area<\/td>\r\n shaded region represents 3\/4 of the area<\/td>\r\n <\/tr>\r\n
51<\/td>\r\n Bottom<\/td>\r\n Missing punctuation<\/td>\r\n length of side AC<\/em> = 5sqrt(2)Using the same figure<\/td>\r\n length of side AC<\/em> = 5sqrt(2).\u00a0 Using the same figure<\/td>\r\n <\/tr>\r\n
57<\/td>\r\n Bottom<\/td>\r\n #18 answer<\/td>\r\n 18.\u00a0 3 and 4:<\/strong><\/td>\r\n 18.\u00a0 3 or 4:<\/strong><\/td>\r\n <\/tr>\r\n
63<\/td>\r\n Top<\/td>\r\n #1 answer (units)<\/td>\r\n 1.\u00a0 256 square units:<\/strong><\/td>\r\n 1.\u00a0 256 inches2<\/sup>:<\/strong><\/td>\r\n <\/tr>\r\n
63<\/td>\r\n Bottom<\/td>\r\n #5 answer (units)<\/td>\r\n 5:\u00a0 20sqrt(2):<\/strong><\/td>\r\n 5.\u00a0 20sqrt(2) meters:<\/strong><\/td>\r\n <\/tr>\r\n
64<\/td>\r\n Top<\/td>\r\n #8 answer (units)<\/td>\r\n 8.\u00a0 4sqrt(3):<\/strong><\/td>\r\n 8.\u00a0 4sqrt(3) inches:<\/strong><\/td>\r\n <\/tr>\r\n
64<\/td>\r\n Top<\/td>\r\n #9 answer (units)<\/td>\r\n 9.\u00a0 16sqrt(3):<\/strong><\/td>\r\n 9.\u00a0 16sqrt(3) cm2<\/sup>:<\/strong><\/td>\r\n <\/tr>\r\n
66<\/td>\r\n Middle<\/td>\r\n #13: Quantity A approximation<\/td>\r\n 1 + 2 + 1.4 + 1.7 = 5.1<\/strong><\/td>\r\n 1 + 2 + 1.4 + 1.7 = 6.1<\/strong><\/td>\r\n <\/tr>\r\n
81<\/td>\r\n Middle<\/td>\r\n #5: The solids are rectangular, not cubes<\/td>\r\n …larger cube is 8 times the volume of the smaller cube.<\/td>\r\n …larger solid is 8 times the volume of the smaller solid.<\/td>\r\n <\/tr>\r\n
81<\/td>\r\n Bottom<\/td>\r\n #8: Clarity<\/td>\r\n 8.\u00a0 20, 21:<\/strong><\/td>\r\n 8.\u00a0 Area = 21, Perimeter = 20:<\/strong><\/td>\r\n <\/tr>\r\n
82<\/td>\r\n Top<\/td>\r\n #9: Clarity<\/td>\r\n 9.\u00a0 28, 48:<\/strong><\/td>\r\n 9.\u00a0 Area = 48, Perimeter = 28:<\/strong><\/td>\r\n <\/tr>\r\n
87<\/td>\r\n Top<\/td>\r\n #2<\/td>\r\n the perimeter is 9 2\/3, or 6 inches.<\/td>\r\n the perimeter is 9 \u00d7 2\/3, or 6 inches.<\/td>\r\n <\/tr>\r\n
102<\/td>\r\n Top<\/td>\r\n 3rd line of text<\/td>\r\n stack of circles, each with an area or pi r<\/em>2<\/sup>.<\/td>\r\n stack of circles, each with an area of pi r<\/em>2<\/sup>.<\/td>\r\n <\/tr>\r\n
106<\/td>\r\n Top<\/td>\r\n #11, 2nd line of text<\/td>\r\n and anglde BAC<\/em> is 45\u00ba<\/td>\r\n and angle BAC<\/em> is 45\u00ba<\/td>\r\n <\/tr>\r\n
110<\/td>\r\n Top<\/td>\r\n #8<\/td>\r\n then Jane will need 0.2 buckets to paint the entire column.<\/td>\r\n then Jane will need 10.2 buckets to paint the entire column.<\/td>\r\n <\/tr>\r\n
111<\/td>\r\n Top<\/td>\r\n 2nd line of text:\u00a0 angle reference<\/td>\r\n Angle A, an inscribed angle,<\/td>\r\n Angle BAC<\/em>, an inscribed angle,<\/td>\r\n <\/tr>\r\n
116<\/td>\r\n Top<\/td>\r\n #2 figure labels<\/td>\r\n 20, x<\/em>, y<\/em>, and z<\/em><\/td>\r\n 20\u00ba, x<\/em>\u00ba, y<\/em>\u00ba, and z<\/em>\u00ba<\/td>\r\n <\/tr>\r\n
116<\/td>\r\n Bottom<\/td>\r\n #3 figure labels<\/td>\r\n a<\/em>, b<\/em>, c<\/em>, and d<\/em><\/td>\r\n a<\/em>\u00ba, b<\/em>\u00ba, c<\/em>\u00ba, and d<\/em>\u00ba<\/td>\r\n <\/tr>\r\n
117<\/td>\r\n Bottom<\/td>\r\n #4 – #5 figure labels<\/td>\r\n a<\/em>, b<\/em>, c<\/em>, d<\/em>, e<\/em>, f<\/em>, g<\/em>, h<\/em><\/td>\r\n a<\/em>\u00ba, b<\/em>\u00ba, c<\/em>\u00ba, d<\/em>\u00ba, e<\/em>\u00ba, f<\/em>\u00ba, g<\/em>\u00ba, h<\/em>\u00ba<\/td>\r\n <\/tr>\r\n
117<\/td>\r\n Bottom<\/td>\r\n #4 and #5 (both)<\/td>\r\n If angle g<\/em> = 120,<\/td>\r\n If g<\/em> = 120,<\/td>\r\n <\/tr>\r\n
119<\/td>\r\n Top<\/td>\r\n #2<\/td>\r\n Because x<\/em> and 20 are supplementary<\/td>\r\n Because x<\/em>\u00ba and 20\u00ba are supplementary<\/td>\r\n <\/tr>\r\n
119<\/td>\r\n Top<\/td>\r\n #2<\/td>\r\n Because y<\/em> and 20 are vertical<\/td>\r\n Because y<\/em>\u00ba and 20\u00ba are vertical<\/td>\r\n <\/tr>\r\n
122<\/td>\r\n Top<\/td>\r\n #16 figure labels<\/td>\r\n a<\/em>, b<\/em>, c<\/em>, d<\/em>, e<\/em>, f<\/em><\/td>\r\n a<\/em>\u00ba, b<\/em>\u00ba, c<\/em>\u00ba, d<\/em>\u00ba, e<\/em>\u00ba, f<\/em>\u00ba<\/td>\r\n <\/tr>\r\n
122<\/td>\r\n Middle<\/td>\r\n #17 figure labels<\/td>\r\n w<\/em>, x<\/em>, y<\/em>, z<\/em><\/td>\r\n w<\/em>\u00ba, x<\/em>\u00ba, y<\/em>\u00ba, z<\/em>\u00ba<\/td>\r\n <\/tr>\r\n
125<\/td>\r\n Top<\/td>\r\n #17 figure labels<\/td>\r\n w<\/em>, x<\/em>, y<\/em>, z<\/em><\/td>\r\n w<\/em>\u00ba, x<\/em>\u00ba, y<\/em>\u00ba, z<\/em>\u00ba<\/td>\r\n <\/tr>\r\n
155<\/td>\r\n Middle<\/td>\r\n #12 Quantity A<\/td>\r\n The y<\/em>-intercept o\\f the line<\/td>\r\n The y<\/em>-intercept of the line<\/td>\r\n <\/tr>\r\n
170<\/td>\r\n Top<\/td>\r\n #5<\/td>\r\n Triangle XYZ<\/em> and Rectangle JKLM<\/em><\/td>\r\n Triangle ABC<\/em> and Rectangle JKLM<\/em><\/td>\r\n <\/tr>\r\n
183<\/td>\r\n Top<\/td>\r\n 3rd line of text<\/td>\r\n so that is the length of Rectangle OPQR<\/em>.<\/td>\r\n so that is the width of Rectangle OPQR<\/em>.<\/td>\r\n <\/tr>\r\n
184<\/td>\r\n Bottom<\/td>\r\n #5 explanation<\/td>\r\n Triangle XYZ<\/em> and Rectangle JKLM<\/em><\/td>\r\n Triangle ABC<\/em> and Rectangle JKLM<\/em><\/td>\r\n <\/tr>\r\n
206<\/td>\r\n Top<\/td>\r\n Clarity<\/td>\r\n …the area A<\/em> of a square and its perimeter is given by…<\/td>\r\n …the area A<\/em> of a square and its perimeter P<\/em> is given by…<\/td>\r\n <\/tr>\r\n
209<\/td>\r\n Top<\/td>\r\n #1 figure<\/td>\r\n {Lines for top front\/right edges of the cube are missing}<\/td>\r\n \u00a0<\/td>\r\n <\/tr>\r\n
213<\/td>\r\n Top<\/td>\r\n #11 figure labels<\/td>\r\n a<\/em>, b<\/em>, c<\/em>, d<\/em>, e<\/em>, f<\/em><\/td>\r\n a<\/em>\u00ba, b<\/em>\u00ba, c<\/em>\u00ba, d<\/em>\u00ba, e<\/em>\u00ba, f<\/em>\u00ba<\/td>\r\n <\/tr>\r\n
217<\/td>\r\n Bottom<\/td>\r\n #20<\/td>\r\n The coordinates of point B are (-3, -4)<\/td>\r\n The coordinates of point B are (-3, +4)<\/td>\r\n <\/tr>\r\n
217<\/td>\r\n Bottom<\/td>\r\n #20<\/td>\r\n The coordinates of point C are (-7, -7)<\/td>\r\n The coordinates of point C are (-7, +7)<\/td>\r\n <\/tr>\r\n
219<\/td>\r\n Top<\/td>\r\n #1<\/td>\r\n arc PQR = 5\/6(4pi) = 20\/6pi = 10\/3pi<\/td>\r\n arc PQR = 5\/6(4pi) = 20pi\/6 = 10pi\/3<\/td>\r\n <\/tr>\r\n
219<\/td>\r\n Top<\/td>\r\n #1 Quantity A<\/td>\r\n 10\/3pi<\/td>\r\n (10\/3)pi<\/td>\r\n <\/tr>\r\n
219<\/td>\r\n Bottom<\/td>\r\n #5<\/td>\r\n Combining, y<\/em> + z<\/em> = 180…<\/td>\r\n Combining, y<\/em> + x<\/em> = 180…<\/td>\r\n <\/tr>\r\n
221<\/td>\r\n Bottom<\/td>\r\n #13<\/td>\r\n …the diagonal QR<\/em> = 12,<\/td>\r\n …the diagonal SQ<\/em> = 12,<\/td>\r\n <\/tr>\r\n
228<\/td>\r\n Bottom<\/td>\r\n #16 answer<\/td>\r\n 16. A:<\/strong><\/td>\r\n 16. E:<\/strong><\/td>\r\n <\/tr>\r\n
229<\/td>\r\n Middle<\/td>\r\n #19 typo, 2nd line<\/td>\r\n supplementarty<\/td>\r\n supplementary<\/td>\r\n <\/tr>\r\n
241<\/td>\r\n Middle<\/td>\r\n #20<\/td>\r\n point D<\/em> is at (-4, -3)<\/td>\r\n point D<\/em> is at (-4, +3)<\/td>\r\n <\/tr>\r\n
241<\/td>\r\n Middle<\/td>\r\n #20<\/td>\r\n point C<\/em> is at (-7, -7)<\/td>\r\n point C<\/em> is at (-7, +7)<\/td>\r\n <\/tr>\r\n <\/tbody>\r\n <\/table>\r\n <\/div>\r\n <\/div>\r\n<\/div>","protected":false},"excerpt":{"rendered":"

Errata – Geometry, 2nd Edition Cover for 2nd Edition 2.0 Page Location Description Erroneous Text Correction 40 Middle #3 explanation shaded region represents 3\/4 the area shaded region represents 3\/4 of the area 51 Bottom Missing punctuation length of side AC = 5sqrt(2)Using the same figure length of side AC = 5sqrt(2).\u00a0 Using the same […]<\/p>\n","protected":false},"author":111,"featured_media":0,"parent":8123,"menu_order":0,"comment_status":"open","ping_status":"open","template":"","meta":{"footnotes":""},"yst_prominent_words":[],"class_list":["post-8203","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/pages\/8203","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/users\/111"}],"replies":[{"embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/comments?post=8203"}],"version-history":[{"count":4,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/pages\/8203\/revisions"}],"predecessor-version":[{"id":8349,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/pages\/8203\/revisions\/8349"}],"up":[{"embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/pages\/8123"}],"wp:attachment":[{"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/media?parent=8203"}],"wp:term":[{"taxonomy":"yst_prominent_words","embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/yst_prominent_words?post=8203"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}