{"id":10541,"date":"2017-08-09T20:09:55","date_gmt":"2017-08-09T20:09:55","guid":{"rendered":"http:\/\/www.manhattanprep.com\/gre\/?p=10541"},"modified":"2019-08-30T16:38:39","modified_gmt":"2019-08-30T16:38:39","slug":"gre-math-for-people-who-hate-math-average-speed","status":"publish","type":"post","link":"https:\/\/www.manhattanprep.com\/gre\/blog\/gre-math-for-people-who-hate-math-average-speed\/","title":{"rendered":"GRE Math for People Who Hate Math: Average Speed"},"content":{"rendered":"<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-10562\" src=\"http:\/\/www.manhattanprep.com\/gre\/wp-content\/uploads\/sites\/19\/2017\/07\/gre-math-people-who-hate-math-average-speed-chelsey-cooley.png\" alt=\"Manhattan Prep GRE Blog - GRE Math for People Who Hate Math: Average Speed by Chelsey Cooley\" width=\"1200\" height=\"628\" srcset=\"https:\/\/www.manhattanprep.com\/gre\/wp-content\/uploads\/sites\/19\/2017\/07\/gre-math-people-who-hate-math-average-speed-chelsey-cooley.png 1200w, https:\/\/www.manhattanprep.com\/gre\/wp-content\/uploads\/sites\/19\/2017\/07\/gre-math-people-who-hate-math-average-speed-chelsey-cooley-300x157.png 300w, https:\/\/www.manhattanprep.com\/gre\/wp-content\/uploads\/sites\/19\/2017\/07\/gre-math-people-who-hate-math-average-speed-chelsey-cooley-768x402.png 768w, https:\/\/www.manhattanprep.com\/gre\/wp-content\/uploads\/sites\/19\/2017\/07\/gre-math-people-who-hate-math-average-speed-chelsey-cooley-1024x536.png 1024w\" sizes=\"auto, (max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><b><i>You can attend the first session of any of our online or in-person GRE courses absolutely free. Crazy, right? <\/i><\/b><a id=\"bloglink\" href=\"https:\/\/www.manhattanprep.com\/gre\/classes\/\" target=\"_blank\" rel=\"noopener\"><b><i>Check out our upcoming courses here<\/i><\/b><\/a><b><i>.<\/i><\/b><\/p>\n<hr \/>\n<p><b><i><\/i><\/b><span style=\"font-weight: 400;\">On the GRE, you will never, ever, ever, <\/span><i><span style=\"font-weight: 400;\">ever<\/span><\/i><span style=\"font-weight: 400;\"> have to average two speeds together. If a GRE Quant problem gives you two speeds (say, 40 mph and 60 mph), and you average them (ending up with 50 mph), you\u2019ve just gotten that problem wrong.<\/span><!--more--><\/p>\n<p><span style=\"font-weight: 400;\">Here\u2019s an example:<\/span><\/p>\n<p style=\"padding-left: 30px;\"><span style=\"font-weight: 400;\">Rajesh drove the 240 miles from Springfield to Greenville at a rate of 40 mph. Then, he returned along the same route at a rate of 60 mph. What was his average speed for the entire trip?<\/span><\/p>\n<p style=\"padding-left: 30px;\"><span style=\"font-weight: 400;\">(A) 42 mph<br \/>\n<\/span><span style=\"font-weight: 400;\">(B) 48 mph<br \/>\n<\/span><span style=\"font-weight: 400;\">(C) 50 mph<br \/>\n<\/span><span style=\"font-weight: 400;\">(D) 54 mph<br \/>\n<\/span><span style=\"font-weight: 400;\">(E) 56 mph<\/span><\/p>\n<p><span style=\"font-weight: 400;\">If you average the two speeds, you\u2019d get (40 mph + 60 mph)\/2 = 50 mph. That answer choice is only there to trap you! <\/span><\/p>\n<p><span style=\"font-weight: 400;\">Here\u2019s what you should do instead. Every time you see the term \u2018average speed\u2019 (or anything similar) in a problem, write the following on your scratch paper right away:<\/span><\/p>\n<p style=\"padding-left: 30px;\"><span style=\"font-weight: 400;\">avg speed = total dist \/ total time<\/span><\/p>\n<p><span style=\"font-weight: 400;\">This formula works every single time. Break it down into pieces to keep yourself organized:<\/span><\/p>\n<p><span style=\"font-weight: 400;\">1. Calculate the total distance traveled. Rajesh traveled 240 miles in one direction, then turned around and traveled 240 miles in the other direction. His total distance was 240 + 240 = 480 miles.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">2. Calculate the total time. For this one, you\u2019ll need a famous formula: <\/span><b>distance = rate * time<\/b><span style=\"font-weight: 400;\">. You\u2019ll also need to calculate the time for each half of the trip separately. For the first half, the distance is 240 miles and the rate is 40 mph. <\/span><\/p>\n<p style=\"padding-left: 30px;\"><span style=\"font-weight: 400;\">240 miles = 40 mph * time<\/span><\/p>\n<p style=\"padding-left: 30px;\"><span style=\"font-weight: 400;\">time = 240 miles \/ 40 mph = 6 hours<\/span><\/p>\n<p><span style=\"font-weight: 400;\">For the second half of the trip, the distance is 240 miles again, and the rate is 60 mph.<\/span><\/p>\n<p style=\"padding-left: 30px;\"><span style=\"font-weight: 400;\">240 miles = 60 mph * time<\/span><\/p>\n<p style=\"padding-left: 30px;\"><span style=\"font-weight: 400;\">time = 240 miles \/ 60 mph = 4 hours<\/span><\/p>\n<p style=\"padding-left: 30px;\"><span style=\"font-weight: 400;\">The total time for the entire trip is 10 hours.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Once you have those pieces, you\u2019re ready to find the actual answer. Plug them into the formula: <\/span><\/p>\n<p style=\"padding-left: 30px;\"><span style=\"font-weight: 400;\">avg speed = total dist \/ total time<\/span><\/p>\n<p style=\"padding-left: 30px;\"><span style=\"font-weight: 400;\">avg speed = 480 miles \/ 10 hours = 48 mph<\/span><\/p>\n<p><span style=\"font-weight: 400;\">The correct answer is 48 mph.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Let\u2019s dig deeper. Does it make sense that the answer is 48 mph? One useful skill for average speed problems is <\/span><i><span style=\"font-weight: 400;\">sanity checking<\/span><\/i><span style=\"font-weight: 400;\"> your answers. Do this by comparing your answer to the other numbers in the problem. Here, 48 is between 40 and 60. That makes sense. It\u2019s slightly below the midpoint of those two numbers: is that where it should be? <\/span><\/p>\n<p><span style=\"font-weight: 400;\">Well, Rajesh went more slowly during the first half of the trip, so he spent a longer time traveling at a lower speed. The longer you travel at a speed, the closer your average will be to that speed. If you walk across America, then hop on a plane and fly back the other way, your average speed for the whole trip will be much closer to your walking speed than to your flying speed. It makes sense that Rajesh\u2019s average was closer to his slower speed of 40 mph. By the way, you could\u2019ve used that to make a fast guess on that problem!<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Here\u2019s something else we can learn from that problem. What if we changed the distance that Rajesh traveled? <\/span><\/p>\n<p style=\"padding-left: 30px;\"><span style=\"font-weight: 400;\">Rajesh drove the <\/span><b>300 miles<\/b><span style=\"font-weight: 400;\"> from Springfield to Greenville at a rate of 40 mph. Then, he returned along the same route at a rate of 60 mph. What was his average speed for the entire trip?<\/span><\/p>\n<p style=\"padding-left: 30px;\"><span style=\"font-weight: 400;\">(F) 42 mph<br \/>\n<\/span><span style=\"font-weight: 400;\">(G) 48 mph<br \/>\n<\/span><span style=\"font-weight: 400;\">(H) 50 mph<br \/>\n<\/span><span style=\"font-weight: 400;\">(I) 54 mph<br \/>\n<\/span><span style=\"font-weight: 400;\">(J) 56 mph<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Does his average speed change? Try working it out, or at least take a guess, before you keep reading.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">His total distance was 600 miles. The time for the first part of the trip was 7.5 hours, and the time for the second part was 5 hours. Plug (600 miles)\/(7.5+5 hours) into your calculator to find that his average speed was 48 mph, yet again.<\/span><\/p>\n<p><span style=\"font-weight: 400;\">That would actually happen no matter what the distance was. The answer <\/span><i><span style=\"font-weight: 400;\">always<\/span><\/i><span style=\"font-weight: 400;\"> comes out to 48 mph. Interestingly, the GRE knows this, so sometimes they won\u2019t even tell you the distance. That\u2019s okay, since the answer is always the same. But how do you calculate the answer? By choosing your own numbers! <\/span><\/p>\n<p><span style=\"font-weight: 400;\">Here\u2019s the rule: <\/span><b>if the GRE doesn\u2019t tell you the distance<\/b><span style=\"font-weight: 400;\">, <\/span><b>you\u2019re allowed to choose it yourself.<\/b><\/p>\n<p><span style=\"font-weight: 400;\">Try it out on this more complicated problem:<\/span><\/p>\n<p style=\"padding-left: 30px;\"><span style=\"font-weight: 400;\">Adrian drove from Springfield to Greenville at a rate of 100 kilometers per hour. Then, he halved his speed to 50 kilometers per hour, and drove from Greenville to Wilmington. If the distance between Greenville and Wilmington is twice the distance from Springfield to Greenville, what was Adrian\u2019s average speed for the entire trip? <\/span><\/p>\n<p><span style=\"font-weight: 400;\">Got your answer? Here\u2019s how I approached it. We don\u2019t know the distances, so we can choose whatever we\u2019re comfortable with, as long as it doesn\u2019t contradict what the problem says. We\u2019ll have to divide the distances by 50 or 100, so let\u2019s choose values that are multiples of those numbers. Let\u2019s say that Springfield and Greenville are 100 kilometers apart, and Greenville and Wilmington are 200 kilometers apart. <\/span><\/p>\n<p><span style=\"font-weight: 400;\">In that case, the total distance would be 300 kilometers. It takes Adrian 1 hour to travel the first 100 kilometers, and 4 hours to travel the remaining 200. His total travel time is 5 hours. Use the formula:<\/span><\/p>\n<p style=\"padding-left: 30px;\"><span style=\"font-weight: 400;\">avg speed = 300 km \/ 5 hours = 60 km\/hr<\/span><\/p>\n<p><span style=\"font-weight: 400;\">If you got the same answer, you should feel confident about GRE average speed problems! All you need is these three tools:<\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">The average speed formula<\/span><\/li>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">Sanity checking<\/span><\/li>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">Choosing your own distance<\/span><\/li>\n<\/ul>\n<p><span style=\"font-weight: 400;\">Good luck! ?<\/span><\/p>\n<hr \/>\n<p><b><i>See that \u201cSUBSCRIBE\u201d button in the top right corner? Click on it to receive all our GRE blog updates straight to your inbox!<\/i><\/b><\/p>\n<hr \/>\n<p><b><i><em><strong><a id=\"bloglink\" href=\"https:\/\/www.manhattanprep.com\/instructors\/chelsey-cooley\/\" target=\"_blank\" rel=\"noopener noreferrer\">Chelsey Cooley<\/a><a href=\"https:\/\/www.manhattanprep.com\/instructors\/chelsey-cooley\/?utm_source=manhattanprep.com%2Fgre%2Fblog&#038;utm_medium=blog&#038;utm_content=CooleyBioGREBlog&#038;utm_campaign=GRE%20Blog\" target=\"_blank\" rel=\"noopener noreferrer\"><img loading=\"lazy\" decoding=\"async\" class=\"alignleft\" title=\"Chelsey Cooley Manhattan Prep GRE Instructor\" src=\"https:\/\/cdn2.manhattanprep.com\/gre\/wp-content\/uploads\/sites\/19\/2015\/11\/chelsey-cooley-150x150.jpg\" alt=\"Chelsey Cooley Manhattan Prep GRE Instructor\" width=\"150\" height=\"150\" data-pin-nopin=\"true\" \/><\/a>\u00a0is a Manhattan Prep instructor based in Seattle, Washington.<\/strong>\u00a0<\/em><\/i><\/b><i><em>Chelsey always followed her heart when it came to her education. Luckily, her heart led her straight to the perfect background for GMAT and GRE teaching: she has undergraduate degrees in mathematics and history, a master\u2019s degree in linguistics, a 790 on the GMAT, and a perfect 170Q\/170V on the GRE.\u00a0<\/em><\/i><i><em><a id=\"bloglink\" href=\"https:\/\/www.manhattanprep.com\/gre\/classes\/#instructor\/48\" target=\"_blank\" rel=\"noopener noreferrer\">Check out Chelsey\u2019s upcoming GRE prep offerings here<\/a>.<\/em><\/i><\/p>\n","protected":false},"excerpt":{"rendered":"<p>You can attend the first session of any of our online or in-person GRE courses absolutely free. Crazy, right? Check out our upcoming courses here. On the GRE, you will never, ever, ever, ever have to average two speeds together. If a GRE Quant problem gives you two speeds (say, 40 mph and 60 mph), [&hellip;]<\/p>\n","protected":false},"author":127,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[2,474284,921840,421,6,7,733451,9,10,733445,154333],"tags":[1362456,390447],"yst_prominent_words":[],"class_list":["post-10541","post","type-post","status-publish","format-standard","hentry","category-challenge-problems","category-current-studiers","category-gre-prep-2","category-gre-quant-2","category-gre-strategies","category-how-to-study","category-life-hacks","category-math-gre-strategies","category-gre-basic-math","category-study-tips-2","category-taking-the-gre-2","tag-average-speed","tag-gre-math-for-people-who-hate-math"],"_links":{"self":[{"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/posts\/10541","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/users\/127"}],"replies":[{"embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/comments?post=10541"}],"version-history":[{"count":3,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/posts\/10541\/revisions"}],"predecessor-version":[{"id":10564,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/posts\/10541\/revisions\/10564"}],"wp:attachment":[{"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/media?parent=10541"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/categories?post=10541"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/tags?post=10541"},{"taxonomy":"yst_prominent_words","embeddable":true,"href":"https:\/\/www.manhattanprep.com\/gre\/wp-json\/wp\/v2\/yst_prominent_words?post=10541"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}