Drill 3: Solve the following inequalities.
2. x/3 +8 < x/2
In the answer it multiplies both sides by 6 to cancel out the bottom fractions. Can you please explain? When I solve the problem I multiply the 3 on both sides to cancel out the three and then multiply by 2 on both sides to cancel out the fraction on the right side. I see why the 6 was used since they both multiply by 6. What I don't see if how I can recognize when to multiply by a number that's not already in the problem while knowing it's still an approved number and not something that's changing the equation. Thanks!