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raghavender.jitta
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Challenge Problem: 2013, January 7 - Jellybean Inequity

by raghavender.jitta Sun Oct 20, 2013 2:06 pm

Please help me understand this.

The problem was posted on 2013, January 7 titled Jellybean Inequity:

Consider this distribution:
A B C D E F | G H I
5 7 7 7 7 7 | 7 7 46

I understand that the question didn’t put say anything about whether two people can have the same number of Jellybeans. But I find it hard to understand how the 6th and 7th person have the same number makes the '3 people w/ the MOST jellybean' statement accurate?

I don't mind if the 7th, 8th and 9th person have the same number of Jellybeans. It is only the 6th and 7th having the same number that concerns me.

Hope to hear from you soon.
tommywallach
Manhattan Prep Staff
 
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Re: Challenge Problem: 2013, January 7 - Jellybean Inequity

by tommywallach Sun Oct 20, 2013 11:03 pm

Hey Raghavender,

I kinda agree with you, to be honest. I'm going to look into this.

-t
raghavender.jitta
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Re: Challenge Problem: 2013, January 7 - Jellybean Inequity

by raghavender.jitta Wed Oct 23, 2013 1:50 am

Hi Tommy,

Thanks for taking your time to answer me. Much appreciated!

Please do get back to me with the correct explanation soon. :)
tommywallach
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Posts: 1917
Joined: Thu Mar 31, 2011 11:18 am
 

Re: Challenge Problem: 2013, January 7 - Jellybean Inequity

by tommywallach Thu Oct 24, 2013 1:48 pm

I just agree that it's written confusingly. Your problem is a fair one. Don't worry about what's correct at this point. What makes it unclear is that you can't really say there is a "top 3" if the top 6 are all the same. Well caught! We'll get it switched up!

-t