Q10

[jhoak12]

Hello,

While on this question I put B. Looking back I can now see how it is possible wrong. I think it is wrong because L does not necessarily have to go on a Monday.

With the set up I grouped: H/S, L/P, and G/K.

After this grouping is where I get lost and I can not seem to figure out why E is the right answer.

Thanks!

[ohthatpatrick]

I would start by writing a (GK) "friend" chunk on my page.

Then I'd look at rules dealing with G or K.

Rule 3 has them together in a conditional. As we look at that rule, we see that we could never place (GK) on Monday, or else we'd be forced to break the rule.

So we could probably place (GK) on Tues or Wed. I would frame those two possibilities.

mon: __ __ , tues: G K , wed: __ __

mon: __ __ , tues: __ __ , wed: G K

What's left to deal with?
LP chunk
GH anti-chunk (don't have to worry about this, since G is with K)
If S-wed, H-tues.

Well the LP chunk could theoretically take either of the remaining two days in each scenario.

Does conditional rule apply to either scenario?
Do I know whether S is on Wed?
Do I know whether H is NOT on Tuesday?

In the first frame, I know that H is NOT on Tuesday, so that means I know that S is NOT on Wed.

That means S must go on Mon.

mon: S __ , tues: G K , wed: __ __

Now I know that LP must go on Wed, leaving H for Mon.

1st FRAME:
mon: S H , tues: G K , wed: L P

In the second frame, we don't have to worry about the 4th rule. Its trigger could never be activated since GK is filling up Wed.

We basically have LP and SH left to float between Mon and Tues.

2nd FRAME:
mon: (LP) <---> tues: (SH) , wed: G K

(A) Nope. H could be on Tues in the 2nd frame.
(B) Nope. L could be on Tues in the 2nd frame.
(C) Nope. K could be on Wed in the 3rd frame.
(D) Nope. P could be Wed in the 1st frame.
(E) Yes, S is only on Mon or Tues.