znT396 wrote:Thank you for the clarification Ron!

When you say backsolving, do you mean plugging in -0.8 for y in |10y-4|>7and y< 1?

Because the answer I got after plugging in -0.8 in the first inequality is -8>11 and 8>11 doesn't make sense...

hm?

math symbols don't mean more than one thing, so it's impossible for "plugging in" to give two results.

| 10y – 4 | > 7

substitute y = –0.8:

| 10(–0.8) – 4 | > 7 ...this is something that will turn out to be either true or false, we just don't know until we simplify it

| –8 – 4 | > 7

| –12 | > 7

12 > 7

this is TRUE (12 is, indeed, greater than 7), so the inequality WORKS.

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i don't know what your concept of "plugging in" entails, but, if your idea of "plugging in" is something that gives you two different results (and neither of them has the numbers 12 and 7 on the left and right, respectively), then you definitely need to ditch your whole notion of "plugging in" and re-learn it from scratch.

"plugging in" is literally just throwing a number into something, doing the arithmetic, and seeing whether the result is true or false.