Given (d/4)+(8/d)+3=0, what is d?

First step of the answer is to multiply the entire equation by 4d (denominator) to get d^2+32+12d=0. When I multiple the equation by 4d I get d^2+8d+3d. What am I doing wrong?

Thanks!

Marco

GMAT Forum

2 postsPage **1** of **1**

- MarcoR557
- Course Students
**Posts:**1**Joined:**Mon Dec 18, 2017 6:56 pm

Given (d/4)+(8/d)+3=0, what is d?

First step of the answer is to multiply the entire equation by 4d (denominator) to get d^2+32+12d=0. When I multiple the equation by 4d I get d^2+8d+3d. What am I doing wrong?

Thanks!

Marco

First step of the answer is to multiply the entire equation by 4d (denominator) to get d^2+32+12d=0. When I multiple the equation by 4d I get d^2+8d+3d. What am I doing wrong?

Thanks!

Marco

- Sage Pearce-Higgins
- ManhattanGMAT Staff
**Posts:**943**Joined:**Thu Apr 03, 2014 4:04 am

When I multiple the equation by 4d I get d^2+8d+3d. What am I doing wrong?

(d/4)+(8/d)+3=0 If we multiply the equation by 4d, then we get:

(4d)(d/4) + (4d)(8/d) + (4d)(3) = 0

Take care to multiply the fractions correctly:

(4)(d^2)/4 + (32d)/d + 12d = 0

Then simplify the fractions by cancelling:

d^2 + 32 + 12d = 0

I don't see exactly what step you take to get your version; it looks like you're not multiplying each term by 4d.

2 posts Page **1** of **1**