by ohthatpatrick Sun Jan 06, 2019 2:03 am
The first thing we would do here is look back at all our previous scenarios and look at who has been S's teammate before. We can immediately get rid of all those answers.
Since we don't have any previous work here (in this thread), we'll just prove all four wrong answers are possible, leaving the impossible correct answer.
We know that S is on G's team, and we know that G's team has to be higher than H's team (so G must be 1 or 2). Thus, S must be 1 or 2.
We also know that P - N, so P must be 1 or 2 and N must be 2 or 3.
Our spidey sense might tell us that N could be the impossible buddy for S, since we know that S must be 1 or 2, and N must be 2 or 3. It's harder for them to be together since S has rules forcing it to be earlier and N has rules forcing it to be later.
The only way they could be together would be if they were both on team 2.
But we know that T is on team 2, so it would never be allowable for (S, N) to be team 2.
This is how we could proactively know that (B) is the answer.
We could otherwise back our way in by writing possible scenarios for the other four answers.
(A)
G: [S, M] ... H: [T, P] ... F: [N, O]
(C)
G: [S, O] ... H: [T, P] ... F: [N, M]
(D)
G: [S, P] ... H: [T, M] ... F: [N, O]
(E)
F: [P, M] ... G: [T, S] ... F: [N, O]